SQL problem - Friend Requests II: Who Has the Most Friends

Problem

Query

SELECT
    id, COUNT(id) as num
FROM
(
    SELECT
        requester_id as id
    FROM
        RequestAccepted r

    UNION ALL

    SELECT
        accepter_id as id
    FROM
        RequestAccepted r
) AS t
GROUP BY
    id
ORDER BY
    num DESC
LIMIT 1

Editorial Solution

Approach 1: Combining Tables Using UNION ALL and Finding the Top Values Using ORDER BY + LIMIT

WITH all_ids AS (
   SELECT requester_id AS id
   FROM RequestAccepted
   UNION ALL
   SELECT accepter_id AS id
   FROM RequestAccepted)
SELECT id,
   COUNT(id) AS num
FROM all_ids
GROUP BY id
ORDER BY COUNT(id) DESC
LIMIT 1

Approach 2: Combining Tables Using UNION ALL and Finding Top Values Using RANK()

WITH all_ids AS (
   SELECT requester_id AS id
   FROM RequestAccepted
   UNION ALL
   SELECT accepter_id AS id
   FROM RequestAccepted)
SELECT id, num
FROM
   (
   SELECT id,
      COUNT(id) AS num,
      RANK () OVER(ORDER BY COUNT(id) DESC) AS rnk
   FROM all_ids
   GROUP BY id
   )t0
WHERE rnk=1